3.6.31 \(\int \cot ^5(c+d x) (a+a \sin (c+d x))^4 \, dx\) [531]

3.6.31.1 Optimal result
3.6.31.2 Mathematica [A] (verified)
3.6.31.3 Rubi [A] (verified)
3.6.31.4 Maple [A] (verified)
3.6.31.5 Fricas [A] (verification not implemented)
3.6.31.6 Sympy [F(-1)]
3.6.31.7 Maxima [A] (verification not implemented)
3.6.31.8 Giac [A] (verification not implemented)
3.6.31.9 Mupad [B] (verification not implemented)

3.6.31.1 Optimal result

Integrand size = 21, antiderivative size = 148 \[ \int \cot ^5(c+d x) (a+a \sin (c+d x))^4 \, dx=\frac {4 a^4 \csc (c+d x)}{d}-\frac {2 a^4 \csc ^2(c+d x)}{d}-\frac {4 a^4 \csc ^3(c+d x)}{3 d}-\frac {a^4 \csc ^4(c+d x)}{4 d}-\frac {10 a^4 \log (\sin (c+d x))}{d}-\frac {4 a^4 \sin (c+d x)}{d}+\frac {2 a^4 \sin ^2(c+d x)}{d}+\frac {4 a^4 \sin ^3(c+d x)}{3 d}+\frac {a^4 \sin ^4(c+d x)}{4 d} \]

output
4*a^4*csc(d*x+c)/d-2*a^4*csc(d*x+c)^2/d-4/3*a^4*csc(d*x+c)^3/d-1/4*a^4*csc 
(d*x+c)^4/d-10*a^4*ln(sin(d*x+c))/d-4*a^4*sin(d*x+c)/d+2*a^4*sin(d*x+c)^2/ 
d+4/3*a^4*sin(d*x+c)^3/d+1/4*a^4*sin(d*x+c)^4/d
 
3.6.31.2 Mathematica [A] (verified)

Time = 0.11 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.65 \[ \int \cot ^5(c+d x) (a+a \sin (c+d x))^4 \, dx=\frac {a^4 \left (48 \csc (c+d x)-24 \csc ^2(c+d x)-16 \csc ^3(c+d x)-3 \csc ^4(c+d x)-120 \log (\sin (c+d x))-48 \sin (c+d x)+24 \sin ^2(c+d x)+16 \sin ^3(c+d x)+3 \sin ^4(c+d x)\right )}{12 d} \]

input
Integrate[Cot[c + d*x]^5*(a + a*Sin[c + d*x])^4,x]
 
output
(a^4*(48*Csc[c + d*x] - 24*Csc[c + d*x]^2 - 16*Csc[c + d*x]^3 - 3*Csc[c + 
d*x]^4 - 120*Log[Sin[c + d*x]] - 48*Sin[c + d*x] + 24*Sin[c + d*x]^2 + 16* 
Sin[c + d*x]^3 + 3*Sin[c + d*x]^4))/(12*d)
 
3.6.31.3 Rubi [A] (verified)

Time = 0.27 (sec) , antiderivative size = 127, normalized size of antiderivative = 0.86, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {3042, 3186, 99, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \cot ^5(c+d x) (a \sin (c+d x)+a)^4 \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {(a \sin (c+d x)+a)^4}{\tan (c+d x)^5}dx\)

\(\Big \downarrow \) 3186

\(\displaystyle \frac {\int \frac {\csc ^5(c+d x) (a-a \sin (c+d x))^2 (\sin (c+d x) a+a)^6}{a^5}d(a \sin (c+d x))}{d}\)

\(\Big \downarrow \) 99

\(\displaystyle \frac {\int \left (a^3 \csc ^5(c+d x)+4 a^3 \csc ^4(c+d x)+4 a^3 \csc ^3(c+d x)-4 a^3 \csc ^2(c+d x)-10 a^3 \csc (c+d x)-4 a^3+a^3 \sin ^3(c+d x)+4 a^3 \sin ^2(c+d x)+4 a^3 \sin (c+d x)\right )d(a \sin (c+d x))}{d}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {\frac {1}{4} a^4 \sin ^4(c+d x)+\frac {4}{3} a^4 \sin ^3(c+d x)+2 a^4 \sin ^2(c+d x)-4 a^4 \sin (c+d x)-\frac {1}{4} a^4 \csc ^4(c+d x)-\frac {4}{3} a^4 \csc ^3(c+d x)-2 a^4 \csc ^2(c+d x)+4 a^4 \csc (c+d x)-10 a^4 \log (a \sin (c+d x))}{d}\)

input
Int[Cot[c + d*x]^5*(a + a*Sin[c + d*x])^4,x]
 
output
(4*a^4*Csc[c + d*x] - 2*a^4*Csc[c + d*x]^2 - (4*a^4*Csc[c + d*x]^3)/3 - (a 
^4*Csc[c + d*x]^4)/4 - 10*a^4*Log[a*Sin[c + d*x]] - 4*a^4*Sin[c + d*x] + 2 
*a^4*Sin[c + d*x]^2 + (4*a^4*Sin[c + d*x]^3)/3 + (a^4*Sin[c + d*x]^4)/4)/d
 

3.6.31.3.1 Defintions of rubi rules used

rule 99
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], 
 x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | 
| (GtQ[m, 0] && GeQ[n, -1]))
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3186
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*tan[(e_.) + (f_.)*(x_)]^(p 
_.), x_Symbol] :> Simp[1/f   Subst[Int[x^p*((a + x)^(m - (p + 1)/2)/(a - x) 
^((p + 1)/2)), x], x, b*Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, m}, x] && E 
qQ[a^2 - b^2, 0] && IntegerQ[(p + 1)/2]
 
3.6.31.4 Maple [A] (verified)

Time = 0.46 (sec) , antiderivative size = 188, normalized size of antiderivative = 1.27

method result size
parallelrisch \(-\frac {3 \left (\sec ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \left (\csc ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \left (\left (\frac {80 \cos \left (2 d x +2 c \right )}{3}-\frac {20 \cos \left (4 d x +4 c \right )}{3}-20\right ) \ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-\frac {80 \cos \left (2 d x +2 c \right )}{3}+\frac {20 \cos \left (4 d x +4 c \right )}{3}+20\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\sin \left (3 d x +3 c \right )+\frac {5 \sin \left (5 d x +5 c \right )}{9}+\frac {\sin \left (7 d x +7 c \right )}{9}+\frac {113 \cos \left (2 d x +2 c \right )}{12}-\frac {55 \cos \left (4 d x +4 c \right )}{12}+\frac {5 \cos \left (6 d x +6 c \right )}{12}-\frac {\cos \left (8 d x +8 c \right )}{96}+\frac {5 \sin \left (d x +c \right )}{9}-\frac {125}{32}\right ) a^{4}}{256 d}\) \(188\)
derivativedivides \(\frac {a^{4} \left (\frac {\left (\cos ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cos ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )+4 a^{4} \left (-\frac {\cos ^{6}\left (d x +c \right )}{\sin \left (d x +c \right )}-\left (\frac {8}{3}+\cos ^{4}\left (d x +c \right )+\frac {4 \left (\cos ^{2}\left (d x +c \right )\right )}{3}\right ) \sin \left (d x +c \right )\right )+6 a^{4} \left (-\frac {\cos ^{6}\left (d x +c \right )}{2 \sin \left (d x +c \right )^{2}}-\frac {\left (\cos ^{4}\left (d x +c \right )\right )}{2}-\left (\cos ^{2}\left (d x +c \right )\right )-2 \ln \left (\sin \left (d x +c \right )\right )\right )+4 a^{4} \left (-\frac {\cos ^{6}\left (d x +c \right )}{3 \sin \left (d x +c \right )^{3}}+\frac {\cos ^{6}\left (d x +c \right )}{\sin \left (d x +c \right )}+\left (\frac {8}{3}+\cos ^{4}\left (d x +c \right )+\frac {4 \left (\cos ^{2}\left (d x +c \right )\right )}{3}\right ) \sin \left (d x +c \right )\right )+a^{4} \left (-\frac {\left (\cot ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )}{d}\) \(243\)
default \(\frac {a^{4} \left (\frac {\left (\cos ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cos ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )+4 a^{4} \left (-\frac {\cos ^{6}\left (d x +c \right )}{\sin \left (d x +c \right )}-\left (\frac {8}{3}+\cos ^{4}\left (d x +c \right )+\frac {4 \left (\cos ^{2}\left (d x +c \right )\right )}{3}\right ) \sin \left (d x +c \right )\right )+6 a^{4} \left (-\frac {\cos ^{6}\left (d x +c \right )}{2 \sin \left (d x +c \right )^{2}}-\frac {\left (\cos ^{4}\left (d x +c \right )\right )}{2}-\left (\cos ^{2}\left (d x +c \right )\right )-2 \ln \left (\sin \left (d x +c \right )\right )\right )+4 a^{4} \left (-\frac {\cos ^{6}\left (d x +c \right )}{3 \sin \left (d x +c \right )^{3}}+\frac {\cos ^{6}\left (d x +c \right )}{\sin \left (d x +c \right )}+\left (\frac {8}{3}+\cos ^{4}\left (d x +c \right )+\frac {4 \left (\cos ^{2}\left (d x +c \right )\right )}{3}\right ) \sin \left (d x +c \right )\right )+a^{4} \left (-\frac {\left (\cot ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )}{d}\) \(243\)
risch \(10 i a^{4} x +\frac {a^{4} {\mathrm e}^{4 i \left (d x +c \right )}}{64 d}+\frac {i a^{4} {\mathrm e}^{3 i \left (d x +c \right )}}{6 d}-\frac {9 a^{4} {\mathrm e}^{2 i \left (d x +c \right )}}{16 d}+\frac {3 i a^{4} {\mathrm e}^{i \left (d x +c \right )}}{2 d}-\frac {3 i a^{4} {\mathrm e}^{-i \left (d x +c \right )}}{2 d}-\frac {9 a^{4} {\mathrm e}^{-2 i \left (d x +c \right )}}{16 d}-\frac {i a^{4} {\mathrm e}^{-3 i \left (d x +c \right )}}{6 d}+\frac {a^{4} {\mathrm e}^{-4 i \left (d x +c \right )}}{64 d}+\frac {20 i a^{4} c}{d}+\frac {4 i a^{4} \left (-6 i {\mathrm e}^{6 i \left (d x +c \right )}+6 \,{\mathrm e}^{7 i \left (d x +c \right )}+15 i {\mathrm e}^{4 i \left (d x +c \right )}-10 \,{\mathrm e}^{5 i \left (d x +c \right )}-6 i {\mathrm e}^{2 i \left (d x +c \right )}+10 \,{\mathrm e}^{3 i \left (d x +c \right )}-6 \,{\mathrm e}^{i \left (d x +c \right )}\right )}{3 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{4}}-\frac {10 a^{4} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}\) \(282\)
norman \(\frac {-\frac {a^{4}}{64 d}-\frac {a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{6 d}-\frac {5 a^{4} \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}+\frac {5 a^{4} \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{6 d}-\frac {3 a^{4} \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}+\frac {5 a^{4} \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{6 d}+\frac {5 a^{4} \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{6 d}-\frac {3 a^{4} \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}+\frac {5 a^{4} \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{6 d}-\frac {5 a^{4} \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}-\frac {a^{4} \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{6 d}-\frac {a^{4} \left (\tan ^{16}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64 d}+\frac {107 a^{4} \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}+\frac {107 a^{4} \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}+\frac {945 a^{4} \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32 d}}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{4}}-\frac {10 a^{4} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {10 a^{4} \ln \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}\) \(342\)

input
int(cos(d*x+c)^5*csc(d*x+c)^5*(a+a*sin(d*x+c))^4,x,method=_RETURNVERBOSE)
 
output
-3/256*sec(1/2*d*x+1/2*c)^4*csc(1/2*d*x+1/2*c)^4*((80/3*cos(2*d*x+2*c)-20/ 
3*cos(4*d*x+4*c)-20)*ln(sec(1/2*d*x+1/2*c)^2)+(-80/3*cos(2*d*x+2*c)+20/3*c 
os(4*d*x+4*c)+20)*ln(tan(1/2*d*x+1/2*c))+sin(3*d*x+3*c)+5/9*sin(5*d*x+5*c) 
+1/9*sin(7*d*x+7*c)+113/12*cos(2*d*x+2*c)-55/12*cos(4*d*x+4*c)+5/12*cos(6* 
d*x+6*c)-1/96*cos(8*d*x+8*c)+5/9*sin(d*x+c)-125/32)*a^4/d
 
3.6.31.5 Fricas [A] (verification not implemented)

Time = 0.27 (sec) , antiderivative size = 144, normalized size of antiderivative = 0.97 \[ \int \cot ^5(c+d x) (a+a \sin (c+d x))^4 \, dx=\frac {24 \, a^{4} \cos \left (d x + c\right )^{8} - 128 \, a^{4} \cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) - 288 \, a^{4} \cos \left (d x + c\right )^{6} + 615 \, a^{4} \cos \left (d x + c\right )^{4} - 270 \, a^{4} \cos \left (d x + c\right )^{2} - 105 \, a^{4} - 960 \, {\left (a^{4} \cos \left (d x + c\right )^{4} - 2 \, a^{4} \cos \left (d x + c\right )^{2} + a^{4}\right )} \log \left (\frac {1}{2} \, \sin \left (d x + c\right )\right )}{96 \, {\left (d \cos \left (d x + c\right )^{4} - 2 \, d \cos \left (d x + c\right )^{2} + d\right )}} \]

input
integrate(cos(d*x+c)^5*csc(d*x+c)^5*(a+a*sin(d*x+c))^4,x, algorithm="frica 
s")
 
output
1/96*(24*a^4*cos(d*x + c)^8 - 128*a^4*cos(d*x + c)^6*sin(d*x + c) - 288*a^ 
4*cos(d*x + c)^6 + 615*a^4*cos(d*x + c)^4 - 270*a^4*cos(d*x + c)^2 - 105*a 
^4 - 960*(a^4*cos(d*x + c)^4 - 2*a^4*cos(d*x + c)^2 + a^4)*log(1/2*sin(d*x 
 + c)))/(d*cos(d*x + c)^4 - 2*d*cos(d*x + c)^2 + d)
 
3.6.31.6 Sympy [F(-1)]

Timed out. \[ \int \cot ^5(c+d x) (a+a \sin (c+d x))^4 \, dx=\text {Timed out} \]

input
integrate(cos(d*x+c)**5*csc(d*x+c)**5*(a+a*sin(d*x+c))**4,x)
 
output
Timed out
 
3.6.31.7 Maxima [A] (verification not implemented)

Time = 0.23 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.81 \[ \int \cot ^5(c+d x) (a+a \sin (c+d x))^4 \, dx=\frac {3 \, a^{4} \sin \left (d x + c\right )^{4} + 16 \, a^{4} \sin \left (d x + c\right )^{3} + 24 \, a^{4} \sin \left (d x + c\right )^{2} - 120 \, a^{4} \log \left (\sin \left (d x + c\right )\right ) - 48 \, a^{4} \sin \left (d x + c\right ) + \frac {48 \, a^{4} \sin \left (d x + c\right )^{3} - 24 \, a^{4} \sin \left (d x + c\right )^{2} - 16 \, a^{4} \sin \left (d x + c\right ) - 3 \, a^{4}}{\sin \left (d x + c\right )^{4}}}{12 \, d} \]

input
integrate(cos(d*x+c)^5*csc(d*x+c)^5*(a+a*sin(d*x+c))^4,x, algorithm="maxim 
a")
 
output
1/12*(3*a^4*sin(d*x + c)^4 + 16*a^4*sin(d*x + c)^3 + 24*a^4*sin(d*x + c)^2 
 - 120*a^4*log(sin(d*x + c)) - 48*a^4*sin(d*x + c) + (48*a^4*sin(d*x + c)^ 
3 - 24*a^4*sin(d*x + c)^2 - 16*a^4*sin(d*x + c) - 3*a^4)/sin(d*x + c)^4)/d
 
3.6.31.8 Giac [A] (verification not implemented)

Time = 0.50 (sec) , antiderivative size = 134, normalized size of antiderivative = 0.91 \[ \int \cot ^5(c+d x) (a+a \sin (c+d x))^4 \, dx=\frac {3 \, a^{4} \sin \left (d x + c\right )^{4} + 16 \, a^{4} \sin \left (d x + c\right )^{3} + 24 \, a^{4} \sin \left (d x + c\right )^{2} - 120 \, a^{4} \log \left ({\left | \sin \left (d x + c\right ) \right |}\right ) - 48 \, a^{4} \sin \left (d x + c\right ) + \frac {250 \, a^{4} \sin \left (d x + c\right )^{4} + 48 \, a^{4} \sin \left (d x + c\right )^{3} - 24 \, a^{4} \sin \left (d x + c\right )^{2} - 16 \, a^{4} \sin \left (d x + c\right ) - 3 \, a^{4}}{\sin \left (d x + c\right )^{4}}}{12 \, d} \]

input
integrate(cos(d*x+c)^5*csc(d*x+c)^5*(a+a*sin(d*x+c))^4,x, algorithm="giac" 
)
 
output
1/12*(3*a^4*sin(d*x + c)^4 + 16*a^4*sin(d*x + c)^3 + 24*a^4*sin(d*x + c)^2 
 - 120*a^4*log(abs(sin(d*x + c))) - 48*a^4*sin(d*x + c) + (250*a^4*sin(d*x 
 + c)^4 + 48*a^4*sin(d*x + c)^3 - 24*a^4*sin(d*x + c)^2 - 16*a^4*sin(d*x + 
 c) - 3*a^4)/sin(d*x + c)^4)/d
 
3.6.31.9 Mupad [B] (verification not implemented)

Time = 9.62 (sec) , antiderivative size = 368, normalized size of antiderivative = 2.49 \[ \int \cot ^5(c+d x) (a+a \sin (c+d x))^4 \, dx=\frac {3\,a^4\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{2\,d}-\frac {a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{6\,d}-\frac {a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{64\,d}-\frac {10\,a^4\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{d}-\frac {104\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}-119\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+120\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9-\frac {1135\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8}{4}+80\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7-73\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+48\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\frac {75\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{2}-\frac {40\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{3}+10\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+\frac {8\,a^4\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{3}+\frac {a^4}{4}}{d\,\left (16\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}+64\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+96\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+64\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+16\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\right )}-\frac {9\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{16\,d}+\frac {10\,a^4\,\ln \left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}{d} \]

input
int((cos(c + d*x)^5*(a + a*sin(c + d*x))^4)/sin(c + d*x)^5,x)
 
output
(3*a^4*tan(c/2 + (d*x)/2))/(2*d) - (a^4*tan(c/2 + (d*x)/2)^3)/(6*d) - (a^4 
*tan(c/2 + (d*x)/2)^4)/(64*d) - (10*a^4*log(tan(c/2 + (d*x)/2)))/d - (10*a 
^4*tan(c/2 + (d*x)/2)^2 - (40*a^4*tan(c/2 + (d*x)/2)^3)/3 + (75*a^4*tan(c/ 
2 + (d*x)/2)^4)/2 + 48*a^4*tan(c/2 + (d*x)/2)^5 - 73*a^4*tan(c/2 + (d*x)/2 
)^6 + 80*a^4*tan(c/2 + (d*x)/2)^7 - (1135*a^4*tan(c/2 + (d*x)/2)^8)/4 + 12 
0*a^4*tan(c/2 + (d*x)/2)^9 - 119*a^4*tan(c/2 + (d*x)/2)^10 + 104*a^4*tan(c 
/2 + (d*x)/2)^11 + a^4/4 + (8*a^4*tan(c/2 + (d*x)/2))/3)/(d*(16*tan(c/2 + 
(d*x)/2)^4 + 64*tan(c/2 + (d*x)/2)^6 + 96*tan(c/2 + (d*x)/2)^8 + 64*tan(c/ 
2 + (d*x)/2)^10 + 16*tan(c/2 + (d*x)/2)^12)) - (9*a^4*tan(c/2 + (d*x)/2)^2 
)/(16*d) + (10*a^4*log(tan(c/2 + (d*x)/2)^2 + 1))/d